1x^2+7x=-11

Solution for 1x^2+7x=-11 equation:

1x^2+7x=-11

We move all terms to the left:

1x^2+7x-(-11)=0

We add all the numbers together, and all the variables

x^2+7x+11=0

a = 1; b = 7; c = +11;
Δ = b2-4ac
Δ = 72-4·1·11
Δ = 5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{5}}{2*1}=\frac{-7-\sqrt{5}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{5}}{2*1}=\frac{-7+\sqrt{5}}{2}
$